Overview of the week of 10/17-10/21:
Monday: We reviewed derivatives of exponential and logarithmic functions
Tuesday: PSAT day
Wednesday: NO class
Thursday: Chain rule/derivatives of logarithmic and exponential functions assessment
Friday: Started covering our last type of derivative (!!!), implicit differentiation (derivatives of non-functions)
Implicit differentiation- writing the derivative when y isn't alone, or when the equation can not be solved for y. An example of when implicit differentiation must be used is x2+y2=1
All year we have been finding the derivative of functions in respect to x (without knowing it)
When finding the derivative of an equation like y=x+1 we would find y'=1 or dy/dx= 1, where dy/dx is the derivative of y and 1 is the derivative of x+1.
Now that y is not always alone, and can be on both sides of the equal sign dy/dx has a much bigger role in our derivatives.
Now that we are finding derivatives of y terms that are more than just y (ex. y2, 3y, 17y2) dy/dx is always part of our equations, because it's part of the derivative of y.
When using implicit differentiation it is important to remember to always write dy/dx because it is part of the derivative of the y term
example: The derivative of x=4y is 1= 4(dy/dx)
- 1 is the derivative of x
- 4(dy/dx) is the derivative of 4y
Example from class:
The steps we took when solving this were:
- Take the derivative
- Collect dy/dx terms on one side of the = (anything else should be moved to the other side)
- Factor out dy/dx
- Divide to get dy/dx alone on one side of the =
**Helpful hint: distributing almost always makes these problems easier
Here is another example from class. This problem involves more than just finding the derivative of an equation:
Implicit differentiation can also be used to find the second derivative of an equation.
- Find the first derivative normally, using implicit derivation
- Find the second derivative (almost always involves the quotient rule)
Here is an example from class:
**Don't forget: when writing the second derivative dy/dx becomes d2y/dx2